EXPERIMENT
OBJECTIVE
Write a C
program to simulate the following file organization techniques
a)
Single level directory b) Two level directory c) Hierarchical
DESCRIPTION
The directory
structure is the organization of files into a hierarchy of folders. In a
single-level directory system, all the files are placed in one directory. There
is a root directory which has all files. It has a simple architectureand there
are no sub directories. Advantage of single level directory system is that it
is easy to find a file in thedirectory. In the two-level directory system, each
user has own user file directory (UFD). The system maintains a master block
that has one entry for each user. This master block contains the addresses of
the directory of the users. When a user job starts or a user logs in, the
system's master file directory (MFD) is searched. When a user refers to a
particular file, only his own UFD is searched. This effectively solves the name
collision problem and isolates users from one another. Hierarchical directory
structure allows users to create their own subdirectories and to organize their
files accordingly. A tree is the most common directory structure. The tree has
a root directory, and every file in the system has a unique path name. A
directory (or subdirectory) contains a set of files or subdirectories.
PROGRAM
1.
SINGLE
LEVEL DIRECTORY ORGANIZATION
#include<stdio.h>
struct
{
char
dname[10],fname[10][10];
int fcnt;
}dir;
void main()
{
int i,ch;
char f[30];
clrscr();
dir.fcnt =
0;
printf("\nEnter
name of directory -- ");
scanf("%s",
dir.dname);
while(1)
{
printf("\n\n
1. Create File\t2. Delete File\t3. Search File \n 4. Display Files\t5.
Exit\nEnter your choice -- ");
scanf("%d",&ch);
switch(ch)
{
case 1:
printf("\n Enter the name of the file -- ");
scanf("%s",dir.fname[dir.fcnt]);
dir.fcnt++;
break;
case 2:
printf("\n Enter the name of the file -- ");
scanf("%s",f);
for(i=0;i<dir.fcnt;i++)
{
if(strcmp(f,
dir.fname[i])==0)
{
printf("File
%s is deleted ",f);
strcpy(dir.fname[i],dir.fname[dir.fcnt-1]);
break;
}
}
if(i==dir.fcnt)
printf("File
%s not found",f);
else
dir.fcnt--;
break;
case 3:
printf("\n Enter the name of the file -- ");
scanf("%s",f);
for(i=0;i<dir.fcnt;i++)
{
if(strcmp(f,
dir.fname[i])==0)
{
printf("File
%s is found ", f);
break;
}
}
if(i==dir.fcnt)
printf("File
%s not found",f);
break;
case 4:
if(dir.fcnt==0)
printf("\n
Directory Empty");
else
{
printf("\n
The Files are -- ");
for(i=0;i<dir.fcnt;i++)
printf("\t%s",dir.fname[i]);
}
break;
default:
exit(0);
}
}
getch();
}
OUTPUT:
Enter name
of directory -- CSE
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 1
Enter the
name of the file -- A
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 1
Enter the
name of the file -- B
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 1
Enter the
name of the file -- C
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 4
The Files
are -- A B C
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 3
Enter the
name of the file – ABC
File ABC not
found
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 2
Enter the
name of the file – B
File B is
deleted
1. Create
File 2. Delete File 3. Search File
4. Display
Files 5. Exit Enter your choice – 5
2.
TWO
LEVEL DIRECTORY ORGANIZATION
#include<stdio.h>
struct
{
char dname[10],fname[10][10];
int fcnt;
}dir[10];
void main()
{
int i,ch,dcnt,k;
char f[30], d[30];
clrscr();
dcnt=0;
while(1)
{
printf("\n\n 1. Create Directory\t 2.
Create File\t 3. Delete File");
printf("\n 4. Search File \t \t 5.
Display \t 6. Exit \t Enter your choice -- ");
scanf("%d",&ch);
switch(ch)
{
case 1: printf("\n Enter name of
directory -- ");
scanf("%s", dir[dcnt].dname);
dir[dcnt].fcnt=0;
dcnt++;
printf("Directory created");
break;
case 2: printf("\n Enter name of the
directory -- ");
scanf("%s",d);
for(i=0;i<dcnt;i++)
if(strcmp(d,dir[i].dname)==0)
{
printf("Enter name of the file --
");
scanf("%s",dir[i].fname[dir[i].fcnt]);
dir[i].fcnt++;
printf("File created");
break;
}
if(i==dcnt)
printf("Directory %s not
found",d);
break;
case 3: printf("\nEnter name of the
directory -- ");
scanf("%s",d);
for(i=0;i<dcnt;i++)
{
if(strcmp(d,dir[i].dname)==0)
{
printf("Enter name of the file --
");
scanf("%s",f);
for(k=0;k<dir[i].fcnt;k++)
{
if(strcmp(f, dir[i].fname[k])==0)
{
printf("File %s is deleted ",f);
dir[i].fcnt--;
strcpy(dir[i].fname[k],dir[i].fname[dir[i].fcnt]);
goto jmp;
}
}
printf("File %s not found",f);
goto jmp;
}
}
printf("Directory %s not
found",d);
jmp : break;
case 4: printf("\nEnter name of the
directory -- ");
scanf("%s",d);
for(i=0;i<dcnt;i++)
{
if(strcmp(d,dir[i].dname)==0)
{
printf("Enter the name of the file --
");
scanf("%s",f);
for(k=0;k<dir[i].fcnt;k++)
{
if(strcmp(f, dir[i].fname[k])==0)
{
printf("File %s is found ",f);
goto jmp1;
}
}
printf("File %s not found",f);
goto jmp1;
}
}
printf("Directory %s not
found",d);
jmp1: break;
case 5: if(dcnt==0)
printf("\nNo Directory's ");
else
{
printf("\nDirectory\tFiles");
for(i=0;i<dcnt;i++)
{
printf("\n%s\t\t",dir[i].dname);
for(k=0;k<dir[i].fcnt;k++)
printf("\t%s",dir[i].fname[k]);
}
}
break;
default:exit(0);
}
}
getch();
}
OUTPUT:
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 1
Enter name of directory -- DIR1
Directory created
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 1
Enter name of directory -- DIR2
Directory created
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 2
Enter name of the directory – DIR1
Enter name of the file -- A1
File created
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 2
Enter name of the directory – DIR1
Enter name of the file -- A2
File created
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 2
Enter name of the directory – DIR2
Enter name of the file -- B1
File created
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 5
Directory Files
DIR1 A1 A2
DIR2 B1
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 4
Enter name of the directory – DIR
Directory not found
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice -- 3
Enter name of the directory – DIR1
Enter name of the file -- A2
File A2 is deleted
1. Create Directory 2. Create File 3.
Delete File
4. Search File 5. Display 6. Exit Enter
your choice – 6
3.
HIERARCHICAL
DIRECTORY ORGANIZATION
#include<stdio.h>
#include<graphics.h>
struct tree_element
{
char name[20];
int x,y,ftype,lx,rx,nc,level;
struct tree_element *link[5];
};
typedef struct tree_element
node; void main()
{
int gd=DETECT,gm;
node *root;
root=NULL;
clrscr();
create(&root,0,"root",0,639,320);
clrscr();
initgraph(&gd,&gm,"c:\\tc\\BGI");
display(root);
getch();
closegraph();
}
create(node **root,int lev,char *dname,int
lx,int rx,int x)
{
int i,gap;
if(*root==NULL)
{
(*root)=(node *)malloc(sizeof(node));
printf("Enter name of dir/file(under
%s) :",dname);
fflush(stdin);
gets((*root)->name);
printf("enter 1 for Dir/2 forfile
:");
scanf("%d",&(*root)->ftype);
(*root)->level=lev;
(*root)->y=50+lev*50;
(*root)->x=x;
(*root)->lx=lx;
(*root)->rx=rx;
for(i=0;i<5;i++)
(*root)->link[i]=NULL;
if((*root)->ftype==1)
{
printf("No of sub
directories/files(for %s):",(*root)->name);
scanf("%d",&(*root)->nc);
if((*root)->nc==0)
gap=rx-lx;
else gap=(rx-lx)/(*root)->nc;
for(i=0;i<(*root)->nc;i++)
create(&((*root)->link[i]),lev+1,(*root)->name,lx+gap*i,lx+gap*i+gap,lx+gap*i+gap/2);
}
else (*root)->nc=0;
}
}
display(node *root)
{
int i;
settextstyle(2,0,4);
settextjustify(1,1);
setfillstyle(1,BLUE);
setcolor(14); if(root!=NULL)
{
for(i=0;i<root->nc;i++)
{
line(root->x,root->y,root->link[i]->x,root->link[i]->y);
}
if(root->ftype==1)
bar3d(root->x-20,root->y-10,root->x+20,root->y+10,0,0); else
fillellipse(root->x,root->y,20,20);
outtextxy(root->x,root->y,root->name);
for(i=0;i<root->nc;i++)
{
display(root->link[i]);
}
}
}
OUTPUT:
Enter Name of dir/file (under root): ROOT
Enter 1 for Dir / 2 For File : 1
No of subdirectories / files (for ROOT) :2
Enter Name of dir/file (under ROOT):USER 1
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for USER 1):1
Enter Name of dir/file (under USER
1):SUBDIR
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for SUBDIR):2
Enter Name of dir/file (under USER 1):
JAVA Enter 1 for Dir /2 for file:1
No of subdirectories /files (for JAVA): 0
Enter Name of dir/file (under SUBDIR):VB
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for VB): 0
Enter Name of dir/file (under ROOT):USER2
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for USER2):2
Enter Name of dir/file (under ROOT):A
Enter 1 for Dir /2 for file:2
Enter Name of dir/file (under USER2):SUBDIR
2
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for SUBDIR
2):2
Enter Name of dir/file (under SUBDIR2):PPL
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for PPL):2
Enter Name of dir/file (under PPL):B
Enter 1 for Dir /2 for file:2
Enter Name of dir/file (under PPL):C
Enter 1 for Dir /2 for file:2
Enter Name of dir/file (under SUBDIR):AI
Enter 1 for Dir /2 for file:1
No of subdirectories /files (for AI): 2
Enter Name of dir/file (under AI):D
Enter 1 for Dir /2 for file:2
Enter Name of dir/file (under AI):E
Enter 1 for Dir /2 for file:2
The Two level Directory is single level directory
ReplyDeleteso,change it
fcnt variable stands for what??
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how to check output for hierarchical level directory in turbo c++
ReplyDeletesuper ji
ReplyDeleteSir,
ReplyDeleteI want programs for implement all file organization Technique:single level directory two level hierarchical DAG
kek pernah liat tu ss-an wkwk
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteThis comment has been removed by the author.
Deletewell done. appreciate your program. thanks
ReplyDeletewell done. appreciate your program. thanks, will be wonderful if graphics is used to display the directory structure. its possible, but need to invest time.
ReplyDelete